c c c ================================================================== subroutine rptt3(ixyz,icoor,maxm,meqn,mwaves,mbc,mx, & ql,qr,aux1,aux2,aux3,maux,imp,impt,bsasdq, & cmbsasdq,cpbsasdq) c ================================================================== c c # Riemann solver in the transverse direction for the c # advection equations. c # c # On input, c c # ql,qr is the data along some one-dimensional slice, as in rpn3 c # This slice is c # in the x-direction if ixyz=1, c # in the y-direction if ixyz=2, or c # in the z-direction if ixyz=3. c c # bsasdq is an array of flux differences that result from a c # transverse splitting (a previous call to rpt3). c # This stands for B^* A^* \Dq but could represent any of c # 6 possibilities, e.g. C^* B^* \Dq, as specified by ixyz c # and icoor (see below). c # Moreover, each * represents either + or -, as specified by c # imp and impt. c c # ixyz indicates the direction of the original Riemann solve, c # called the x-like direction in the table below: c c # x-like direction y-like direction z-like direction c # ixyz=1: x y z c # ixyz=2: y z x c # ixyz=3: z x y c c # icoor indicates direction in which the transverse solve should c # be performed. c # icoor=2: split in the y-like direction. c # icoor=3: split in the z-like direction. c c # For example, c # ixyz=1, icoor=3 means bsasdq=B^*A^*\Dq, and should be c # split in z into c # cmbsasdq = C^-B^*A^*\Dq, c # cpbsasdq = C^+B^*A^*\Dq. c # c # ixyz=2, icoor=3 means bsasdq=C^*B^*\Dq, and should be c # split in x into c # cmbsasdq = A^-C^*B^*\Dq, c # cpbsasdq = A^+C^*B^*\Dq. c c # The parameters imp and impt are generally needed only if aux c # arrays are being used, in order to access the appropriate c # variable coefficients: c # imp = 1 if bsasdq = B^*A^- \Dq, a left-going flux difference c # 2 if bsasdq = B^*A^+ \Dq, a right-going flux difference c # impt = 1 if bsasdq = B^-A^* \Dq, a down-going flux difference c # 2 if bsasdq = B^+A^* \Dq, an up-going flux difference c c # aux2(:,:,2) is a 1d slice of the aux array along the row c # where the data ql, qr lie. c # aux1(:,:,2) and aux3(:,:,2) are neighboring rows in the c # y-like direction c # aux2(:,:,1) and aux2(:,:,3) are neighboring rows in the c # z-like direction c c implicit real*8(a-h,o-z) dimension ql(1-mbc:maxm+mbc, meqn) dimension qr(1-mbc:maxm+mbc, meqn) dimension bsasdq(1-mbc:maxm+mbc, meqn) dimension cmbsasdq(1-mbc:maxm+mbc, meqn) dimension cpbsasdq(1-mbc:maxm+mbc, meqn) dimension aux1(1-mbc:maxm+mbc, maux, 3) dimension aux2(1-mbc:maxm+mbc, maux, 3) dimension aux3(1-mbc:maxm+mbc, maux, 3) c c c # set iuvw = 1 for u, 2 for v, 3 for w component of velocity c # depending on transverse direction: iuvw = ixyz + icoor - 1 if (iuvw.gt.3) iuvw = iuvw-3 c do 10 i=2-mbc,mx+mbc i1 = i-2+imp !# = i-1 for amdq, i for apdq if (icoor == 2) then !! double-transverse dir. is the y-like direction if (impt == 1) then cmbsasdq(i,1) = dmin1(aux2(i1,iuvw,1),0.d0)*bsasdq(i,1) cpbsasdq(i,1) = dmax1(aux3(i1,iuvw,1),0.d0)*bsasdq(i,1) elseif (impt == 2) then cmbsasdq(i,1) = dmin1(aux2(i1,iuvw,3),0.d0)*bsasdq(i,1) cpbsasdq(i,1) = dmax1(aux3(i1,iuvw,3),0.d0)*bsasdq(i,1) endif else !! double-transverse dir. is the z-like direction if (impt == 1) then !! bmasdq is split into cmbmasdq and cpbmasdq cmbsasdq(i,1) = dmin1(aux1(i1,iuvw,2),0.d0)*bsasdq(i,1) cpbsasdq(i,1) = dmax1(aux1(i1,iuvw,3),0.d0)*bsasdq(i,1) elseif (impt == 2) then !! bpasdq is split into cmbpasdq and cpbpasdq cmbsasdq(i,1) = dmin1(aux3(i1,iuvw,2),0.d0)*bsasdq(i,1) cpbsasdq(i,1) = dmax1(aux3(i1,iuvw,3),0.d0)*bsasdq(i,1) endif endif 10 continue c return end